How to extract file/files from a zip file

.util.zip provides classes to extract, read and

write zip files.

Example below extracts files from given zip file into destination folder. import java.io.*;
import java.util.zip.*;

class testZipFiles
{
public static void main(String[] args)
{
if (args.length != 1)
{
System.out.println("Usage: java testFiles [zipfile path] ");
return;
}
try
{
String filename = args[0];
testZipFiles list = new testZipFiles( );
list.getZipFiles(filename);
}
catch (Exception e)
{
e.printStackTrace();
}
}

public void getZipFiles(String filename)
{
try
{
String destinationname = "d:\\servlet\\testZip\\";
byte[] buf = new byte[1024];
ZipInputStream zipinputstream = null;
ZipEntry zipentry;
zipinputstream = new ZipInputStream(
new FileInputStream(filename));

zipentry = zipinputstream.getNextEntry();
while (zipentry != null)
{
//for each entry to be extracted
String entryName = zipentry.getName();
System.out.println("entryname "+entryName);
int n;
FileOutputStream fileoutputstream;
File newFile = new File(entryName);
String directory = newFile.getParent();

if(directory == null)
{
if(newFile.isDirectory())
break;
}

fileoutputstream = new FileOutputStream(
destinationname+entryName);

while ((n = zipinputstream.read(buf, 0, 1024)) > -1)
fileoutputstream.write(buf, 0, n);

fileoutputstream.close();
zipinputstream.closeEntry();
zipentry = zipinputstream.getNextEntry();

}//while

zipinputstream.close();
}
catch (Exception e)
{
e.printStackTrace();
}
}
}